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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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आशुतोष बिंदू A पासून 19 किमी पश्चिमेकडे जातो. त्यानंतर तो डावीकडे वळतो, 9 किमी चालतो, पुन्हा डावीकडे वळतो आणि 26 किमी चालतो. त्यानंतर तो पुन्हा डावीकडे वळतो आणि 19 किमी चालतो. तो शेवटी डावीकडे वळतो, 7 किमी चालतो आणि बिंदू P वर थांबतो. बिंदू A वर परत पोहोचण्यासाठी त्याला किती दूर (सर्वात कमी अंतर) आणि कोणत्या दिशेने जावे लागेल? (निर्दिष्ट केल्याशिवाय सर्व वळणे 90 अंशांची आहेत.)
दक्षिणेकडे 11 किमी
उत्तरेकडे 11 किमी
उत्तरेकडे 10 किमी
दक्षिणेकडे 10 किमी
दक्षिणेकडे 10 किमी
Track the net displacement using coordinates: set start point A at (0,0). Sum movements: West is -X, East is +X, North is +Y, South is -Y.
Track the net displacement using coordinates: set start point A at (0,0). Sum movements: West is -X, East is +X, North is +Y, South is -Y.
Coordinate Mapping
Start A at (0,0). Moves: 1. 19 km West (-19, 0). 2. Left (South)₉ km (-19, -9). 3. Left (East)₂₆ km (-19+26 = 7, -9). 4. Left (North)₁₉ km (7, -9+19 = 10). 5. Left (West)₇ km (7-7 = 0, 10). Wait, re-reading: Ashutosh is at (0, 10). Distance is 10 km South.
Net Result Calculation
Ashutosh's final position P relative to A(0,0) is (0, 10). Since the X-coordinate is 0 and Y-coordinate is +10 (North), he must move 10 km South to reach (0,0).
A: 11 km South is incorrect; the Y-displacement is exactly 10 km. B: 11 km North increases the gap to 21 km. C: 10 km North would move him to 20 km North of A.
D is correct because his final position is 10 km exactly North of Point A, requiring a 10 km movement to the South to return to the start.
Always assign coordinates (0,0) to the starting point to handle multiple turns without losing track of relative distance.