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Pipe A can fill a tank in 10 hours, and Pipe B can fill it in 15 hours. If both are opened together, how long will it take to fill the tank?
6 hours
5 hours
8 hours
7.5 hours
6 hours
Use the formula (Product / Sum): (10├Ч15)/(10+15)=150/25=6.
Pipe A can fill a tank in 10 hours (T1 = 10) and Pipe B can fill it in 15 hours (T2 = 15).
T=T1тАЛ+T2тАЛT1тАЛ├ЧT2тАЛтАЛ
Use the formula (Product / Sum): (10├Ч15)/(10+15)=150/25=6.
Many students try to calculate the average by doing (10+15)/2 = 12.5, which is incorrect because time taken is inversely proportional to efficiency.
Define efficiency of individual pipes
Pipe A fills 1/10 of the tank per hour, and Pipe B fills 1/15 of the tank per hour.
EfficiencyAтАЛ=101тАЛ,EfficiencyBтАЛ=151тАЛ
Calculate combined efficiency
When both pipes work together, add their hourly rates: 1/10+1/15=3/30+2/30=5/30.
Combined=305тАЛ=61тАЛ
Determine total time
Since they fill 1/6 of the tank per hour, the time required to fill the whole tank is the reciprocal of the combined efficiency.
Time=1/61тАЛ=6
A is correct because the combined work rate of 1/6 of the tank per hour implies the tank will be full in 6 hours.
This concept is identical to solving problems involving two people completing a task at different speeds; always remember that RateAтАЛ+RateBтАЛ=TotalRate.