Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
Point Q is 5m to the east of Point P. Point R is 5m to the north of Point Q. What is the shortest distance between P and R?
5m
10m
5√2m
25m
5√2m
Use Pythagoras theorem for right-angled triangles: shortest distance is the square root of the sum of squares of the two perpendicular movements.
Use Pythagoras theorem for right-angled triangles: shortest distance is the square root of the sum of squares of the two perpendicular movements.
Map the Positions
Point Q is 5m east of P, establishing a horizontal baseline of 5m.
Incorporate Vertical Movement
Point R is 5m north of Q, creating a vertical line perpendicular to the horizontal baseline.
Calculate Shortest Distance
The straight-line distance between P and R forms the hypotenuse of a right-angled triangle with sides 5m and 5m. Calculated as square root of (5 squared + 5 squared) = square root of 50 = 5√2m.
A: 5m only accounts for a single side, B: 10m incorrectly adds the two distances together instead of finding the diagonal, D: 25m is an incorrect arithmetic calculation.
C is correct because the shortest distance between P and R forms the hypotenuse of a right-angled triangle with perpendicular sides of 5m each, yielding square root of (5 squared + 5 squared) which equals 5√2m.
For direction problems asking for shortest distance, always visualize or sketch a right-angled triangle and apply the Pythagorean theorem rather than adding distances directly.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants