Potential difference between two points of a wire carrying 2 a... | General Science MCQ | Examoogle

General SciencePhysics: Electricity

Potential difference between two points of a wire carrying 2 ampere current is 0.1 volt. What is the resistance between these points ?

2 ohm

0.5 ohm

0.05 ohm

20 ohm

None of the above

Correct Answer

⚙️ TE • Technical Concept & PrincipleGeneral SciencePhysics: Electricity

Option C

0.05 ohm

Quick Summary:

The resistance of a conductor is determined by the ratio of the potential difference across it to the current flowing through it. According to Ohm's Law, dividing the given voltage of $0.1 \text{ V}$ by the current of $2 \text{ A}$ yields a resistance of $0.05 \text{ } \Omega$ .

🔬SCScience SolutionConcept & Principle

💡 Explanation

💡 Everyday Analogy (Real-World Intuition)

Think of voltage as the water pressure pushing through a pipe and current as the flow of water; resistance is like the narrowness of the pipe that restricts how much water can pass through for a given pressure.

🧠 Memory Mnemonic / Shortcut Aid

V-I-R triangle: Put $V$ on top and $I, R$ at the bottom. Cover the variable you need to find ( $R = \frac{V}{I}$ ).

🔢 Key Formulas

$V = I \times R$ — Ohm's Law

$R = \frac{V}{I}$ — Calculation of resistance

⚙️ Working Principle

The relationship is governed by Ohm's Law, which states that the current flowing through a metallic conductor is directly proportional to the potential difference across its ends, provided the temperature remains constant. The formula is expressed as $V = I \times R$ , where $V$ is potential difference, $I$ is current, and $R$ is resistance. Rearranging this gives $R = \frac{V}{I}$ .

📌 Key Points

▸
Ohm's Law holds for metallic conductors under constant temperature.
▸
The SI unit of resistance is the Ohm ( $\Omega$ ).
▸
A potential difference of $1 \text{ V}$ across a resistor with $1 \text{ A}$ current results in $1 \text{ } \Omega$ resistance.

✅ Advantages

▸
Predictable circuit behavior in linear components.

❌ Disadvantages / Limitations

▸
Does not apply to non-ohmic components like diodes or transistors.

🛠️ Applications / Uses

▸
Calculating resistor values in electronic circuits.
▸
Designing heating elements based on load requirements.

📄 Additional Information

▸
The calculation performed is $R = \frac{0.1 \text{ V}}{2 \text{ A}} = 0.05 \text{ } \Omega$ .
▸
Option A is incorrect as it assumes $R = V \times I$ ( $0.1 \times 2 = 0.2$ not 2).
▸
Option B is incorrect as it is the inverse $I/V$ ( $2/0.1 = 20$ ).

📊 Diagram / Illustration

✅

C is correct — The resistance is calculated as the potential difference divided by the current, resulting in $0.05 \text{ } \Omega$ .

Core Concepts Used

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Ohm's Law Electrical Resistance Potential Difference

💡 EXAM TIP

Always ensure units are in standard SI (Volts, Amperes, Ohms) before performing calculations to avoid conversion errors.

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