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Potential V=2xy2z3+3ln(x2+2y2+3z2) V in a free space. Magnitude of Electric field intensity at point P(3,2,-1) in direction ax will be _________ V/m.
7.1
7.1
22.8
22.8
7.1
Practice and solve "Potential V = 2xy2z3+3ln(x2+2y2+3z2) V in a free space. Magnitude of Electric field intensity at poi..." for Electrical - Electromagnetics Field Theory . The correct answer is Option A: 7.1. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.
Option **(b) **