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Rahul walks 8 km towards North, then turns left and walks 6 km. He turns right and walks 4 km. Finally, he turns right and walks 6 km. How far is he from the starting point?
12 km
14 km
10 km
18 km
12 km
Track the net North-South and East-West displacement separately: Net Vertical = 8 + 4 = 12 km, Net Horizontal = 6 - 6 = 0 km.
Track the net North-South and East-West displacement separately: Net Vertical = 8 + 4 = 12 km, Net Horizontal = 6 - 6 = 0 km.
Calculate North-South Displacement
Rahul walks 8 km North (+8Y). Later, he turns right (facing North means turning right leads to East) and walks 6 km. Then turns right again (facing East means turning right leads to South) and walks 4 km (-4Y). Total North-South distance = 8 - 4 = 4 km North.
Calculate East-West Displacement
Initial walk North involves 0 East-West. Then, he turns left (facing North means turning left leads to West) and walks 6 km (-6X). Finally, he turns right (facing South means turning right leads to West) - wait, recalculating: 1. North 8 km. 2. Left (West) 6 km. 3. Right (North) 4 km. 4. Right (East) 6 km. Net displacement: Y = 8 + 4 = 12 km North. X = -6 + 6 = 0 km. Total distance = 12 km.
B: 14 km is incorrect as it does not follow the Pythagorean or linear summation of the net path. C: 10 km is a common trap using a 6-8-10 Pythagorean triplet logic which is irrelevant here. D: 18 km is incorrect as it incorrectly sums all individual segments without considering the directions.
A is correct because the net displacement is 12 km due to the person moving 12 km North and 0 km East/West from the starting point.
Always draw a quick coordinate sketch; if the turns result in a return to the same vertical/horizontal axis, simply add the segments in that direction.
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