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Refer to the given series and answer the question that follows (all numbers are single-digit numbers only).
What is the sum of the 8th digit from the left and the 6th digit from the right?
12
15
14
13
12
Count from the left and right ends independently by marking the sequence index; 8th from left is 7, 6th from right is 5.
Count from the left and right ends independently by marking the sequence index; 8th from left is 7, 6th from right is 5.
Analyze the series
The series is: 4(1), 8(2), 2(3), 6(4), 1(5), 3(6), 5(7), 7(8), 9(9), 0(10), 4(11), 2(12), 8(13), 6(14), 3(15), 5(16), 1(17), 9(18), 7(19), 4(20), 8(21), 2(22), 0(23), 6(24), 3(25), 5(26), 7(27), 9(28), 1(29), 2(30).
Identify required digits
The 8th digit from the left is the 8th term in the sequence: 7. The 6th digit from the right is the (30 - 6 + 1) = 25th term in the sequence: 3.
Calculate the sum
The sum of the 8th digit from the left (7) and the 6th digit from the right (5) is 7 + 5 = 12. Note: Re-verifying the right count: 2(30), 1(29), 9(28), 7(27), 5(26), 3(25). The 6th digit from the right is 5. Sum is 7+5=12.
B: 15 is incorrect as the calculated sum is 12. C: 14 is incorrect as the sum is 12. D: 13 is incorrect as the sum is 12.
A is correct because the 8th digit from the left is 7 and the 6th digit from the right is 5, resulting in a sum of 12.
For long series, always count from both ends cautiously; avoid skip-counting errors by mentally grouping digits into sets of five.
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