Find the LCM of the Divisors

$\text{LCM}(3, 4, 5, 6) = 2^2 \times 3 \times 5 = 60$

Common divisor is 60

Divide 2488 by the LCM

$2488 = 60 \times 41 + 28$ The remainder is 28.

$\text{Remainder} = 28$

Calculate the Number to be Added

$\text{Number to add} = \text{Divisor} - \text{Remainder} = 60 - 28 = 32$ Then, $2488 + 32 = 2520$, which is exactly divisible by 60.

$\text{Least positive number to add} = 32$