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Subtract the sum of 2x−3y+7z and 4z−5x from 13x−z.
16x+3y−12z
x+12y−12z
16x−3y+12z
16x+3y−8z
16x+3y−12z
Subtracting Sum of (2x - 3y + 7z) and (4z - 5x) from (13x - z)
Expressions to sum: (2x−3y+7z) and (4z−5x); Target expression: (13x−z)
Find the Sum of the First Two Polynomials
Sum=(2x−3y+7z)+(−5x+4z) Combine like terms: x-terms: 2x−5x=−3xy-terms: −3yz-terms: 7z+4z=11zSum=−3x−3y+11z
Sum =−3x−3y+11z
Subtract Sum from (13x - z)
(13x−z)−(−3x−3y+11z)=13x−z+3x+3y−11z Combine like terms: (13x+3x)+3y+(−z−11z)=16x+3y−12z
Result =16x+3y−12z
Option D is correct — 16x + 3y - 12z