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A can complete a piece of work in 20 days and B can do the same work in 15 days. B worked alone for 6 days and left. In how many days can A complete the remaining work alone?
10
12
10 1/2
16
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Calculate remaining work after B leaves and divide by A's daily efficiency
A's time = 20 days, B's time = 15 days, B worked alone for 6 days
Assume Total Work
Let Total Work = LCM(20,15)=60 units.
Find Efficiencies
• A's efficiency = 2060=3 units/day • B's efficiency = 1560=4 units/day
Work Done by B and Remaining Work
• Work done by B in 6 days = 6×4=24 units • Remaining work = 60−24=36 units
Time Taken by A Alone
Time taken by A=3 units/day36 units=12 days
A completes the remaining work in 12 days.
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