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The present ages of three persons are in ratio 4:5:6. Eight years ago, the sum of their ages was 51. Find the present age of the eldest person.
28 years
30 years
45 years
36 years
30 years
Let present ages be 4x, 5x, and 6x. Eight years ago, their ages were 4xтИТ8, 5xтИТ8, and 6xтИТ8. The sum of these ages is (4xтИТ8)+(5xтИТ8)+(6xтИТ8)=51. Solve for x and multiply by 6 for the eldest person.
The present ages of three persons are in the ratio 4 : 5 : 6. Eight years ago, the sum of their ages was 51.
Present┬аAges=4x,5x,6x
Let present ages be 4x, 5x, and 6x. Eight years ago, their ages were 4xтИТ8, 5xтИТ8, and 6xтИТ8. The sum of these ages is (4xтИТ8)+(5xтИТ8)+(6xтИТ8)=51. Solve for x and multiply by 6 for the eldest person.
Students often forget to subtract 8 years from all three persons, subtracting 8 only once instead of 8├Ч3=24 years in total.
Step 1: Assume present ages in terms of x
Since the present ages are in the ratio 4:5:6, let the present ages of the three persons be 4x, 5x, and 6x respectively.
Present┬аAges=4x,5x,6x
Step 2: Express ages 8 years ago
Eight years ago, the ages of the three persons were (4xтИТ8), (5xтИТ8), and (6xтИТ8).
Ages=(4xтИТ8),(5xтИТ8),(6xтИТ8)
Step 3: Set up the equation from the given sum
The sum of their ages 8 years ago was given as 51. Adding the expressions and equating to 51: (4xтИТ8)+(5xтИТ8)+(6xтИТ8)=51.
15xтИТ24=51
Step 4: Solve for x
Adding 24 to both sides: 15x=51+24=75. Dividing by 15 gives x=5.
x=1575тАЛ=5
Step 5: Find the present age of the eldest person
The eldest person has a ratio of 6, so their present age is 6x=6├Ч5=30 years.
Eldest┬аAge=6├Ч5=30┬аyears
B is correct because solving the equation for the sum of their ages 8 years ago yields x = 5, making the present age of the eldest person 6 ├Ч5=30years.
Age-related word problems frequently appear in competitive exams and can be solved quickly by setting up a single linear equation in terms of a ratio multiplier x.