Join 60,000+ competitive exam aspirants
A and B can together complete a piece of work in 5 days. They worked together for 4 days and then B left. After another 2 days, A completed the remaining work. In how many days can A complete the entire work alone?
20
10
15
5
10
Assume total work = 5 units (LCM of 5 days). In 4 days, A and B complete 4 units of work. The remaining 1 unit is done by A in 2 days, meaning A's 1-day work (efficiency) is 1/2 units/day. Thus, to complete the entire 5 units, A takes 5 / (1/2) = 10 days.
A and B together can complete a work in 5 days (i.e. (A+b)'s 1-day work = 1/5). They worked together for 4 days, then B left. A completed the remaining work in another 2 days.
W=Time├ЧEfficiency
Assume total work = 5 units (LCM of 5 days). In 4 days, A and B complete 4 units of work. The remaining 1 unit is done by A in 2 days, meaning A's 1-day work (efficiency) is 1/2 units/day. Thus, to complete the entire 5 units, A takes 5 / (1/2) = 10 days.
Students often add A's days and B's days directly or forget that A worked for 2 days after 4 days of joint work, making A's total working days on the remaining task 2 days.
Calculate work done in joint days
Since A and B together can complete the work in 5 days, their combined 1-day work is 51тАЛ. They work together for 4 days, so the amount of work completed is $$4 \times \frac{1}{5} = \frac{4}{5}$.
Work┬аdone=54тАЛ
Find remaining work
The remaining fraction of the work after 4 days is $$1 - \frac{4}{5} = \frac{1}{5}$.
Remaining┬аwork=51тАЛ
Determine A's 1-day work (efficiency)
A completes this remaining 51тАЛ of the work in 2 days. Therefore, A's 1-day work is $$\frac{1/5}{2} = \frac{1}{10}$.
AтАЩs┬аefficiency=101тАЛ
Calculate total days for A alone
Since A's daily rate of work is 101тАЛ of the total work per day, A can complete the entire work alone in 1/101тАЛ=10 days.
Total┬аdays=10
B is correct because A's 1-day work is calculated as 1/10, meaning A alone can finish the entire work in 10 days.
Similar unit-rate concepts apply to pipe and cistern problems, where filling and emptying rates replace individual work efficiencies.