Step 1: Define Variables

Let the marks obtained by the second student be $x$. Since the first student secured 9 marks more than the second, the marks of the first student are $x + 9$.

$x \text{ and } x + 9$

Step 2: Express the Given Condition

The sum of their marks is $(x) + (x + 9) = 2x + 9$. According to the problem, the first student's marks are $56\%$ of this sum.

$x + 9 = 0.56(2x + 9)$

Step 3: Solve the Linear Equation

Expand the right side: $x + 9 = 1.12x + 5.04$. Rearrange terms to solve for $x$: $9 - 5.04 = 1.12x - x \implies 3.96 = 0.12x \implies x = \frac{3.96}{0.12} = 33$.

$x = 33$

Step 4: Find Both Students' Marks

The second student's marks are $33$, and the first student's marks are $33 + 9 = 42$. Thus, the marks obtained are 42 and 33.

$42 \text{ and } 33$