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The value of x2тИТ5 at x=тИТ1 is:
2
5
1
4
4
Substitute x=тИТ1 directly into the expression. Remember that the square of any negative number is positive.
Expression: x2тИТ5, Value of x: x=тИТ1
Value=(x)2тИТ5
Substitute x=тИТ1 directly into the expression. Remember that the square of any negative number is positive.
Confusing (тИТ1)2 with тИТ12. (тИТ1)2=+1, whereas тИТ12=тИТ(12)=тИТ1.
Step 1: Write down the given expression and value
We are given the algebraic expression x2тИТ5 and the value x=тИТ1.
Expression=x2тИТ5,x=тИТ1
Step 2: Substitute x=тИТ1 into the expression
Replace every instance of x with (тИТ1), making sure to use parentheses for correct exponentiation.
(тИТ1)2тИТ5
Step 3: Evaluate the exponent
Calculate (тИТ1)2, which equals 1 because the product of two negative numbers is positive.
(тИТ1)2=1
Step 4: Perform the final subtraction
Subtract 5 from 1 to find the final value.
1тИТ5=тИТ4
D is correct because substituting x=тИТ1 into x2тИТ5 yields (тИТ1)2тИТ5=1тИТ5=тИТ4.
Always wrap negative numbers in parentheses when substituting into even powers to avoid sign errors.
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