Join 60,000+ competitive exam aspirants
The work done by a constant force of 5 Newton acting on a body is 5 joules. The displacement of the body in the direction of the applied force is ______.
100 m
10 m
1 m
1000 m
1 m
When a constant force is applied on a body and it moves in the direction of the applied force, the work done is given by the product of force and displacement. Using the formula W=F├Чs, for W=5┬аJ and F=5┬аN, the displacement is s=FWтАЛ=55тАЛ=1┬аm.
When a constant force is applied on a body and it moves in the direction of the applied force, the work done is given by the product of force and displacement. Using the formula W=F├Чs, for W=5┬аJ and F=5┬аN, the displacement is s=FWтАЛ=55тАЛ=1┬аm.
If you push a toy car with a force of 5┬аNewtons and it takes 5┬аJoules of energy to move it straight ahead by 1┬аmeter, the distance covered in the direction of your push is exactly 1┬аmeter.
Remember 'Work equals Force times Displacement': W=F├Чs (Work is Fast).
W=FтЛЕs=FтЛЕscos(╬╕) тАФ Work done by a force
s=FWтАЛ тАФ Displacement in the direction of force
Work done (W) by a constant force is defined as the scalar product (dot product) of the force vector (F) and the displacement vector (s). Mathematically, W=Fscos(╬╕), where ╬╕ is the angle between the force and displacement vectors. Since the motion is in the direction of the applied force, ╬╕=0┬░ and cos(0┬░)=1, which simplifies the equation to W=F├Чs. Rearranging gives s=FWтАЛ.
Work is a scalar quantity, defined as the dot product of force and displacement vectors.
The SI unit of work is Joule (J), which is equivalent to Newton-meter (NтЛЕm or kgтЛЕm2тЛЕsтИТ2).
When force and displacement are in the exact same direction, ╬╕=0┬░, maximizing the work done (W=F├Чs).
Simple linear relationship between force, displacement, and work done for constant forces.
Assumes force is constant and acting along a straight path in the direction of displacement.
Calculating mechanical energy transfer in simple machines.
Determining displacement of objects pushed or pulled on level floors.
Option A (100┬аm) is incorrect because 5/5=1, not 100.
Option B (10┬аm) is incorrect because it overestimates the displacement by a factor of 10.
Option D (1000┬аm) is incorrect and mathematically inconsistent with the given values.
C is correct тАФ The displacement of the body in the direction of the applied force is 1 m.
In competitive exams like RRBALP, always verify the units of work (Joules=NтЛЕm) before applying simple algebraic formulas like W=F├Чs.