Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
Magnification produced by a spherical mirror is equal to __________.
Image distanceObject distance
Height of the objectHeight of the image
Height of the image×height of the object
Object distance×image distance
Height of the objectHeight of the image
Magnification (m) is a ratio that describes how much larger or smaller an image is compared to the original object. It is fundamentally defined as the ratio of the height of the image (h′) to the height of the object (h).
Magnification (m) is a ratio that describes how much larger or smaller an image is compared to the original object. It is fundamentally defined as the ratio of the height of the image (h′) to the height of the object (h).
Think of it like a zoom feature on a camera; if you zoom in, the image height becomes larger than the object height, resulting in a magnification value greater than 1.
Remember 'H-I-H-O': Height of Image over Height of Object.
m=hh′ — Magnification as the ratio of image height (h′) to object height (h)
m=−uv — Magnification in terms of image distance (v) and object distance (u) for spherical mirrors
In spherical optics, the lateral magnification quantifies the change in size of an image formed by a mirror or lens. It is calculated by comparing the perpendicular height of the image to the principal axis against the height of the object. According to the sign convention, a negative value for magnification indicates an inverted image, while a positive value indicates an erect image.
Magnification is a dimensionless quantity.
If ∣m∣>1, the image is magnified; if ∣m∣<1, the image is diminished.
A negative sign for m implies the image is real and inverted, while a positive sign implies it is virtual and erect.
Provides a quick mathematical way to determine the size and orientation of an optical image.
Design of optical instruments like telescopes and microscopes.
Corrective eyewear prescription calculations.
The mirror formula relates object distance (u), image distance (v), and focal length (f) as v1+u1=f1.
Option A is the reciprocal of the magnification formula related to distances, Option C is an incorrect product, and Option D is dimensionally inconsistent.
B is correct — Magnification is defined as the ratio of the height of the image to the height of the object.
Always remember the negative sign in the formula m=−uv for mirrors, which is crucial for distinguishing between real and virtual images.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants