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The relation between thrust (T), pressure (P) and area (A) of an object in a given medium is ______.
P = T / A
T = P / A
A = P / T
P = T × A
P = T / A
Thrust (T) is the total perpendicular force exerted by an object on a surface, while pressure (P) is the force acting per unit surface area (A). The fundamental relationship governing these three physical quantities is given by the product of pressure and area, expressed as T=P×A.
Thrust (T) is the total perpendicular force exerted by an object on a surface, while pressure (P) is the force acting per unit surface area (A). The fundamental relationship governing these three physical quantities is given by the product of pressure and area, expressed as T=P×A.
Imagine pressing a sharp pin versus a blunt stick into a soft board with the same force (thrust). Because the pin has a much smaller area, the pressure exerted is extremely high, whereas for the blunt stick with a larger area, the pressure is much lower.
Remember 'PAT' — Pressure multiplied by Area gives Thrust (T=P×A).
P=AT — Pressure equals thrust divided by area
T=P×A — Thrust equals pressure multiplied by area
Pressure is defined as force per unit area, mathematically written as P=AT, where T represents the thrust (normal force). Rearranging this formula to solve for thrust yields T=P×A. This means the total thrust experienced by a surface depends directly on the intensity of the pressure acting on it and the total surface area over which that pressure is distributed.
Thrust is a vector quantity representing the normal (perpendicular) force acting on a surface.
Pressure is a scalar quantity defined as thrust per unit area.
SI unit of Thrust is Newton (N) or kgf.
SI unit of Pressure is Pascal (Pa) or N/m2.
Helps in understanding fluid mechanics and solid mechanics behavior.
Designing foundations of buildings to distribute weight over a larger area.
Sharp cutting edges (knives, needles) designed with minimal area to maximize pressure.
Option A (T=P×A) correctly rearranges the pressure formula.
Options B, C, and D propose incorrect dimensional relations between the three quantities.
A is correct — The correct relation between thrust (T), pressure (P), and area (A) is given by the equation T = P ×A.
Always verify dimensional consistency when dealing with mechanics formulas: Pressure ([ML−1T−2]) multiplied by Area ([L2]) yields Force/Thrust ([MLT−2]).
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