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If 5cosθ+4sinθ18cosθ+5sinθ=2, then find the value of cotθ.
31
53
83
71
83
Use cross-multiplication immediately: set the numerator equal to 2 times the denominator, then group all cos terms on one side and sin terms on the other to form a ratio of sin/cos or cos/sin.
An equation involving trigonometric ratios: (18 cos theta + 5 sin theta) / (5 cos theta + 4 sin theta) = 2.
ccosθ+dsinθacosθ+bsinθ=k
Use cross-multiplication immediately: set the numerator equal to 2 times the denominator, then group all cos terms on one side and sin terms on the other to form a ratio of sin/cos or cos/sin.
Students often make sign errors during the transposition of terms or incorrectly invert the ratio (finding tan theta instead of cot theta).
Cross-Multiply the Equation
Multiply the denominator by the right-hand side constant 2 to eliminate the fraction.
18cosθ+5sinθ=2(5cosθ+4sinθ)
Expand and Group Terms
Distribute the 2 across the brackets and collect all cosθ terms on one side and sinθ terms on the other.
18cosθ+5sinθ=10cosθ+8sinθ
Simplify the Equation
Subtract 10cosθ from both sides and 5sinθ from both sides to isolate the trigonometric functions.
18cosθ−10cosθ=8sinθ−5sinθ⟹8cosθ=3sinθ
Find cot theta
Divide both sides by sinθ and by 8 to get the value of cotθ=sinθcosθ.
sinθcosθ=83⟹cotθ=83
C is correct because the final simplification leads to \cot \theta =$$\frac{3}{8}.
This method of isolating variables is identical to solving simultaneous equations; always check if the ratio required is sin/cos (tan) or cos/sin (cot) to avoid inversion errors.