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In order to pass in an examination, a student is required to get 780 marks out of the maximum aggregate marks. Sonal got 728 marks and was declared failed by 5%. What is the maximum aggregate marks that a student can get in the examination?
1140
1100
1000
1040
1040
Calculate the difference in marks (780 - 728 = 52) and equate it to the given failure percentage (5%), so 5% of M = 52, thus M = 52 / 0.05 = 52 * 20 = 1040.
Pass marks = 780, Sonal marks = 728, Failure margin = 5% of maximum marks (M)
M=0.05780тИТ728тАЛ
Calculate the difference in marks (780 - 728 = 52) and equate it to the given failure percentage (5%), so 5% of M = 52, thus M = 52 / 0.05 = 52 * 20 = 1040.
Many students subtract 5% from 780 or try to calculate 5% of 780; the failure is 5% of the total maximum aggregate M.
Define the passing criteria
Let the maximum aggregate marks be M. The passing marks are given as 780.
Pass┬аMarks=780
Set up the equation
Sonal got 728 marks and failed by 5% of the total marks M. The shortfall of 52 marks represents the 5% margin.
0.05├ЧM=780тИТ728
Solve for M
Subtracting the marks gives 52. Dividing by 0.05 (or multiplying by 20) yields the total.
M=0.0552тАЛ=1040
D is correct because the difference of 52 marks corresponds to 5% of the total, resulting in a maximum aggregate of 1040.
This relates to profit/loss and basic percentage change problems where the gap between two values is expressed as a percentage of the total.
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