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A sum of money is to be distributed among four members A, B, C, and D in the ratio 4:7:9:3. If C gets ₹720 more than D, find A's share.
₹160
₹480
₹240
₹360
₹480
Calculate the difference between C and D's ratio units (9 - 3 = 6 units). Equate 6 units = 720. So 1 unit = 120. A's share is 4 units = 4 * 120 = 480.
Ratio of shares of A, B, C, and D is 4:7:9:3. C gets ₹720 more than D.
x=Difference in ratiosDifference in values
Calculate the difference between C and D's ratio units (9 - 3 = 6 units). Equate 6 units = 720. So 1 unit = 120. A's share is 4 units = 4 * 120 = 480.
Students often mistakenly use the total sum or compare C with other members instead of D as specified in the question.
Define the ratio variables
Let the common multiplier for the ratio 4:7:9:3 be x. Thus, the shares are: A = 4x, B = 7x, C = 9x, and D = 3x.
A=4x,B=7x,C=9x,D=3x
Set up the equation based on given data
The problem states C gets ₹720 more than D. This can be expressed as C−D=720.
9x−3x=720
Solve for x
Simplify the expression: 6x=720. Therefore, x=6720=120.
x=120
Calculate A's share
Since A's share is 4x, substitute x=120 into the expression: A=4×120=480.
A=480
B is correct because the share of A is calculated to be ₹480 based on the ratio multiplier of 120.
This ratio-based logic is frequently used in Partnership, Profit & Loss, and Age problems in competitive exams.