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Match the correct value from Column II with Column I (Square of a number).
| Column I (Number) | Column II (Square) |
|---|---|
| A. $12^2$ | 1. $196$ |
| B. $13^2$ | 2. $144$ |
| C. $14^2$ | 3. $169$ |
Choose the correct answer from the options given below:
49
35
27
None of these
27
Calculate the total parts (4+5=9). Divide the total (63) by 9 to get 7 per part. Multiply B's ratio part (5) by 7 to get 35.
Total chocolates = 63, Ratio of A:B = 4:5
B=Sum┬аof┬аRatiosRatio┬аof┬аBтАЛ├ЧTotal, Sum┬аof┬аRatios=4+5=9
Calculate the total parts (4+5=9). Divide the total (63) by 9 to get 7 per part. Multiply B's ratio part (5) by 7 to get 35.
Students often miscalculate by dividing the total number of chocolates by the ratio value of A (4) or just by one of the parts, rather than the sum of ratio parts.
Sum the ratio parts
To find the total number of parts in the distribution, add the ratio parts of A and B.
4+5=9
Calculate value per part
Divide the total quantity of chocolates by the sum of the ratio parts.
963тАЛ=7
Determine B's share
Multiply the value of one part by B's ratio portion (5).
5├Ч7=35
C is correct because multiplying B's share of the ratio (5) by the unit value (7) results in 35.
This unitary method is fundamental for Mixture and Allegation problems. Always ensure you find the 'value of one part' before calculating individual quantities.
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