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In order to pass in an examination, a student is required to get 975 marks out of the maximum aggregate marks. Priya got 870 marks and was declared failed by 7%. What is the maximum aggregate marks that a student can get in the examination?
1000
1200
1500
1400
1500
Calculate the difference in marks (975 - 870 = 105). Since 7% of total marks equals 105, total marks M = 105 / 0.07 = 1500.
Pass marks = 975, Marks obtained by Priya = 870, Percentage by which Priya failed = 7%
M=D%тАЛPdiffтАЛтАЛ├Ч100
Calculate the difference in marks (975 - 870 = 105). Since 7% of total marks equals 105, total marks M = 105 / 0.07 = 1500.
Confusing the failed-by-percentage (7%) with the passing percentage; here 7% of the total aggregate is simply the difference between the passing marks and obtained marks.
Calculate the marks deficit
The student needs 975 marks to pass but got 870. The difference is the marks they were short by.
105=975тИТ870
Identify the percentage relationship
Since the student was declared failed by 7%, it means 7% of the maximum marks is equal to the 105 marks difference.
7%├ЧMax┬аMarks=105
Calculate the maximum marks
Solving for maximum marks (M), we divide the deficit by the percentage.
M=0.07105тАЛ=1500
C is correct because the difference of 105 marks between the passing requirement and Priya's score corresponds to exactly 7% of the total aggregate, resulting in a maximum of 1500.
This concept of 'difference in values vs percentage' is frequently applied in profit-loss and speed-distance problems in competitive exams.
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