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If the mode of a data exceeds its mean by 16.2, then the mode exceeds the median by ______. (Use empirical formula to find the answer.)
12.4
10.8
8.25
10.2
10.8
Use the relationship ModeтИТMedian=31тАЛ(ModeтИТMean). Simply divide the given difference by 3.
Mode exceeds mean by 16.2. Mathematically, ModeтИТMean=16.2.
ModeтИТMean=3(MedianтИТMean)
Use the relationship ModeтИТMedian=31тАЛ(ModeтИТMean). Simply divide the given difference by 3.
Confusing the empirical formula coefficients; remember the sequence is Mode=3MedianтИТ2Mean.
Establish the relationship
The empirical relation between mean, median, and mode is given by Mode=3MedianтИТ2Mean.
Mode=3MedianтИТ2Mean
Rearrange the formula
To express the difference (ModeтИТMedian), we rewrite the formula: ModeтИТMedian=3MedianтИТ2MeanтИТMedian=2MedianтИТ2Mean=2(MedianтИТMean). Alternatively, subtract Mean from both sides: ModeтИТMean=3MedianтИТ3Mean=3(MedianтИТMean).
ModeтИТMean=3(MedianтИТMean)
Solve for the difference
Given ModeтИТMean=16.2, we find the difference between median and mean: 16.2=3(MedianтИТMean), so MedianтИТMean=5.4. Now, we need the difference ModeтИТMedian. Using ModeтИТMedian=2(MedianтИТMean), we get 2├Ч5.4=10.8.
ModeтИТMedian=10.8
B is correct because the application of the empirical formula ModeтИТMean=3(MedianтИТMean) yields ModeтИТMedian=10.8.
This empirical relationship is frequently tested in exams; memorize it as Mode=3MedianтИТ2Mean to quickly derive any requested difference between these three measures.