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Radhika's teacher is 60 years old. He is 20 years older than twice Radhika's age. Radhika's age is:
25 years
15 years
20 years
30 years
20 years
Subtract 20 from the teacher's age (60 - 20 = 40), then divide by 2 (40 / 2 = 20) to find Radhika's age.
Teacher's age = 60 years. Teacher is 20 years older than twice Radhika's age.
T=2R+20
Subtract 20 from the teacher's age (60 - 20 = 40), then divide by 2 (40 / 2 = 20) to find Radhika's age.
Many students subtract 20 from 60 and then stop, or misinterpret 'twice Radhika's age' by adding 20 before multiplying.
Define variables
Let Radhika's age be R. The teacher's age is given as 60.
T=60,R=?
Set up the equation
According to the problem, the teacher is 20 years older than twice Radhika's age.
60=2R+20
Solve for R
Subtract 20 from both sides, then divide by 2.
60−20=2R⟹40=2R⟹R=20
C is correct because 60 - 20 = 40, and 40 / 2 = 20 years.
This type of linear algebraic equation is common in RRB exams; always check if the final answer satisfies the original sentence statement: 2(20) + 20 = 60.
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