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A sum of money is to be distributed among four members A, B, C, and D in the ratio 4:7:9:3. If C gets ₹720 more than D, find D's share.
₹360
₹160
₹240
₹480
₹360
Find the difference in ratio units for C and D (9 - 3 = 6 units), equate to the actual difference (6 units = ₹720), then find 1 unit (120) and multiply by D's ratio (3 × 120 = 360).
Ratio of shares of A, B, C, and D is 4:7:9:3. The difference between C's share and D's share is ₹720.
C−D=(9x−3x)=6x=720
Find the difference in ratio units for C and D (9 - 3 = 6 units), equate to the actual difference (6 units = ₹720), then find 1 unit (120) and multiply by D's ratio (3 × 120 = 360).
Many students subtract the wrong ratio values or misinterpret 'more than' as a sum instead of a difference.
Define the ratio variables
Let the shares of members A, B, C, and D be 4x, 7x, 9x, and 3x respectively.
A=4x,B=7x,C=9x,D=3x
Formulate the equation
Since C gets ₹720 more than D, we calculate the difference between their ratio shares: 9x−3x=720.
6x=720
Calculate the value of x
Divide the total difference by the number of units: x=6720=120.
x=120
Find D's share
Substitute x=120 into D's share expression (3x): 3×120=360.
D=3×120=360
A is correct because the difference of 6x units equals ₹720, making x=120, so D's share 3x=₹360.
This concept of 'units' in ratios is fundamental to solving problems in Mixtures, Partnerships, and Ages.