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Pipe R can empty a full tank in 30 hours. But two pipes P and Q can fill the tank in 15 hours and 10 hours, respectively. Ram unknowingly opened all three taps. After 2 hours Shyam realised it and closed Pipe R. Due to this mistake how much time more would it take to fill the tank?
1 hour 20 min
24 min
2 hours 15 min
18 min
24 min
Calculate individual efficiencies: P=2, Q=3, R=-1. Net efficiency for first 2 hours = (2+3-1)=4 units/hr. 2 hours work = 8 units. Remaining = 22 units. New efficiency (P+Q) = 2+3=5. Time = 22/5 = 4.4 hours. Total time is 4.4, but the question asks 'how much time more', which usually implies total time needed minus the 2 hours already passed = 4.4 - 2 = 2.4 hours (2 hours 24 minutes).
Pipe R empties in 30 hours, Pipe P fills in 15 hours, Pipe Q fills in 10 hours. All three pipes are open for 2 hours, then R is closed.
Total┬аCapacity=LCM(15,10,30)=30┬аunits, Efficiency=TimeWorkтАЛ, Time=EfficiencyRemainingWorkтАЛ
Calculate individual efficiencies: P=2, Q=3, R=-1. Net efficiency for first 2 hours = (2+3-1)=4 units/hr. 2 hours work = 8 units. Remaining = 22 units. New efficiency (P+Q) = 2+3=5. Time = 22/5 = 4.4 hours. Total time is 4.4, but the question asks 'how much time more', which usually implies total time needed minus the 2 hours already passed = 4.4 - 2 = 2.4 hours (2 hours 24 minutes).
Students often calculate the total time required instead of the additional time requested, or forget that R is an outlet pipe and should be treated as negative efficiency.
Calculate Efficiencies
Assuming total tank capacity is the LCM of (15, 10, 30) = 30 units. The efficiencies are: P = 30/15 = +2, Q = 30/10 = +3, R = 30/30 = -1 (since it empties).
EPтАЛ=2,EQтАЛ=3,ERтАЛ=тИТ1
Work Done in First 2 Hours
With all three pipes open, net efficiency is 2+3тИТ1=4 units/hr. In 2 hours, they fill 4├Ч2=8 units.
Work2hтАЛ=8┬аunits
Calculate Remaining Work
After 2 hours, remaining capacity = Total Capacity - Work Done = 30тИТ8=22 units.
WremтАЛ=22┬аunits
Calculate Additional Time
After closing R, only P and Q work. New efficiency = 2+3=5 units/hr. Time required = 22/5=4.4 hours. 0.4┬аhours=0.4├Ч60=24 minutes.
Time=4┬аhrs┬а24┬аmin
B is correct because the remaining 22 units filled by pipes P and Q at 5 units/hour take 4.4 hours, which is 4 hours 24 minutes.
This is a standard Time and Work variation; always treat inlet pipes as positive and outlet pipes as negative efficiency.