Join 60,000+ competitive exam aspirants
A sum of money lent on simple interest becomes 58тАЛ of itself in 4 years. Find the rate of interest per annum.
15%
12%
10%
6%
15%
If a sum becomes n times in T years, the rate R=T(nтИТ1)├Ч100тАЛ. Here, n=58тАЛ=1.6, so R=4(1.6тИТ1)├Ч100тАЛ=40.6├Ч100тАЛ=15%.
A sum becomes 8/5 of itself in 4 years on simple interest.
R=P├ЧT100├Ч(AтИТP)тАЛ
If a sum becomes n times in T years, the rate R=T(nтИТ1)├Ч100тАЛ. Here, n=58тАЛ=1.6, so R=4(1.6тИТ1)├Ч100тАЛ=40.6├Ч100тАЛ=15%.
Confusing the total amount A=58тАЛP with the simple interest SI itself; always remember SI=AтИТP=(58тАЛтИТ1)P=53тАЛP.
Define variables
Let the principal be P. Given that the amount A becomes 58тАЛP in T=4 years.
A=58тАЛP
Calculate Simple Interest (SI)
The interest is the difference between the amount and the principal: SI=AтИТP=58тАЛPтИТP=53тАЛP.
SI=0.6P
Apply SI formula
Use the formula SI=100P├ЧR├ЧTтАЛ to solve for R.
0.6P=100P├ЧR├Ч4тАЛ
Solve for Rate (R)
Cancel P from both sides and solve: 0.6=1004RтАЛ, which gives R=460тАЛ=15%.
R=15%
A is correct because the calculated interest rate per annum is 15%.
This concept is a precursor to compound interest problems where the amount is calculated as A=P(1+R/100)n instead of linear growth.