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The difference between the ages of two siblings is 7 years. If the sum of their ages is 21 years, how old is the elder of the siblings?
7 years
3 years
10 years
14 years
14 years
For two values with given sum S and difference D, the larger value is always (S+D)/2 and the smaller is (SтИТD)/2.
Difference between ages = 7 years, Sum of ages = 21 years.
x+y=21, xтИТy=7
For two values with given sum S and difference D, the larger value is always (S+D)/2 and the smaller is (SтИТD)/2.
Confusing the elder age with the younger age, which would be (21тИТ7)/2=7.
Define variables
Let the age of the elder sibling be x and the younger sibling be y. We are given two equations based on the problem statement.
x+y=21; xтИТy=7
Solve the system of equations
Add the two equations to eliminate y and solve for x: (x+y)+(xтИТy)=21+7, which simplifies to 2x=28.
2x=28
Calculate the final age
Divide by 2 to find the age of the elder sibling x.
x=228тАЛ=14
D is correct because the elder sibling is 14 years old, derived from (21+7)/2=14.
This concept of finding two numbers given their sum and difference is fundamental in solving ratio and proportion problems and speed/distance problems involving upstream/downstream motion.