Addition of $ 22 ext{ kg } 589 ext{ g}$ and $ 19 ext{ kg } 678 ext{ g}$ results in:

Question

Addition of $ 22	ext{ kg } 589	ext{ g}$ and $ 19	ext{ kg } 678	ext{ g}$ results in:

Examoogle · Accepted Answer

The correct answer is Option C: $42	ext{ kg } 267	ext{ g}$. Add kilograms (22 + 19 = 41) and grams (589 + 678 = 1267). Since 1267 g = 1 kg 267 g, add the 1 kg to 41 to get 42 kg, leaving 267 g.

Step-by-Step Solution & Concepts:
Shortcut Trick: Add kilograms (22 + 19 = 41) and grams (589 + 678 = 1267). Since 1267 g = 1 kg 267 g, add the 1 kg to 41 to get 42 kg, leaving 267 g.

Formula Used: $$(A_{kg} 	ext{ kg } B_{g}) + (C_{kg} 	ext{ kg } D_{g}) = (A+C)_{kg} 	ext{ kg } (B+D)_{g}$$, where if $B+D \ge 1000$, add $1$ to $kg$ and subtract $1000$ from $g$.

Given: Value 1: 22 kg 589 g, Value 2: 19 kg 678 g

Steps: Sum the kilograms: Add the kilogram components separately: $22 	ext{ kg} + 19 	ext{ kg} = 41 	ext{ kg}$.. Sum the grams: Add the gram components separately: $589 	ext{ g} + 678 	ext{ g} = 1267 	ext{ g}$.. Convert excess grams to kilograms: Since $1000 	ext{ g} = 1 	ext{ kg}$, $1267 	ext{ g}$ is equal to $1 	ext{ kg } 267 	ext{ g}$. Add this to the previous $41 	ext{ kg}$.

Answer: C is correct because the sum of 22 kg 589 g and 19 kg 678 g equals 42 kg 267 g after carrying over 1 kg from the grams column.

Exam Tip: This logic of 'carrying over' is identical to operations in time (minutes to hours) and currency (paise to rupees), where 60 or 100 serves as the base instead of 1000.

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