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Find the value of 38−[27−(90÷5−(12−18÷6)÷3)].
26
22
25
24
26
Solve from the innermost parenthesis outwards. Always process divisions inside parentheses first before subtractions to maintain order of operations.
An arithmetic expression 38−[27−(90÷5−(12−18÷6)÷3)]
BODMAS:Brackets,Orders,Division,Multiplication,Addition,Subtraction
Solve from the innermost parenthesis outwards. Always process divisions inside parentheses first before subtractions to maintain order of operations.
Many students subtract before dividing within the brackets (e.g., calculating 12−18 first) instead of following the order 18÷6.
Solve innermost parenthesis
Inside the innermost brackets, divide before subtracting: 12−(18÷6)=12−3=9.
12−18÷6=9
Simplify the next level
Substitute back: 90÷5−(9÷3). Calculate division first: 18−3=15.
18−3=15
Final calculation
Substitute into the main expression: 38−[27−15]. Resolve the bracket: 27−15=12. Finally, subtract: 38−12=26.
38−12=26
A is correct because the step-by-step simplification of the expression following the BODMAS rule results in 26.
This order of operations is essential for all algebra problems; always prioritize division and multiplication before addition and subtraction.
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