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Select the odd one out from the given options: (A) ACE (B) GIK (C) MOQ (D) PRT
ACE
GIK
MOQ
PRT
PRT
Observe the constant gap of +2 between all consecutive letters in the clusters; the odd one will deviate from this uniform arithmetic sequence.
Observe the constant gap of +2 between all consecutive letters in the clusters; the odd one will deviate from this uniform arithmetic sequence.
Mapping letter positions
Convert letters to their numerical positions: A=1, C=3, E=5; G=7, I=9, K=11; M=13, O=15, Q=17; P=16, R=18, T=20.
Analyzing the gaps
Calculate the difference between consecutive letters: ACE (1+2=3, 3+2=5), GIK (7+2=9, 9+2=11), MOQ (13+2=15, 15+2=17), PRT (16+2=18, 18+2=20). Wait, re-checking gaps: Actually, all follow +2. Let's look for an alternative pattern: vowel inclusion or alphabetical sequence continuity.
Re-evaluating the odd one out
ACE, GIK, and MOQ are sequences of alternating letters (skipping one letter). ACE skips B, D. GIK skips H, J. MOQ skips N, P. PRT is P(16), R(18), T(20). All follow +2. However, looking at the letters: ACE, GIK, and MOQ contain all consonants or start/end with vowels? No. Let's re-verify the sequences: ACE (A is vowel), GIK (I is vowel), MOQ (O is vowel). PRT has no vowels.
A, B, and C are incorrect because they each contain at least one vowel (A, I, O respectively), whereas PRT consists entirely of consonants.
D is correct because PRT is the only letter cluster in the set that does not contain a vowel, while the others contain A, I, and O respectively.
In letter-based odd-one-out questions, if all options follow the same numerical gap rule, immediately check for vowel-consonant composition or physical properties of the letters.