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Select the set in which the numbers are related in the same way as are the numbers of the following sets. (NOTE : Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 тАУ Operations on 13 suchas adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed) (100, 15) (118, 18)
(94, 14)
(100, 16)
(80, 13)
(120, 17)
(94, 14)
Calculate the relationship as Term1 = (Term2 - 1) * 7 + 7 or Term1 = 7 * Term2 - 5. Check if the ratio/gap is consistent across sets.
Calculate the relationship as Term1 = (Term2 - 1) * 7 + 7 or Term1 = 7 * Term2 - 5. Check if the ratio/gap is consistent across sets.
Analyze the given sets
Set 1: (100, 15). Calculate 15 multiplied by 7 = 105. 105 - 5 = 100. Set 2: (118, 18). Calculate 18 multiplied by 7 = 126. 126 - 8 = 118. This suggests a variable subtraction based on the multiplier.
Identify the consistent logic
Alternatively, look at the difference: 100 divided by 7 is approx 14.28. Let us test (Term2 - 1) * 7 + 7. For 15: (15-1)7 + 2 = 98+2=100. For 18: (18-1)7 + 1 = 119+1=120 (Not118). Let's use: Term1 = (Term2 * 6) + 10. For 15: 156 + 10 = 90 + 10 = 100. For 18: 186 + 10 = 108 + 10 = 118. The logic is Term1 = (Term2 * 6) + 10.
Apply logic to options
Test Option A (94, 14): 14 * 6 + 10 = 84 + 10 = 94. This matches perfectly.
B: 166+10 = 106, not 100. C: 136+10 = 88, not 80. D: 17*6+10 = 112, not 120.
A is correct because the relationship follows the formula Term1 = (Term2 * 6) + 10, which yields 94 for the input 14.
In number analogy, if simple addition/subtraction fails, always check the (n * multiplier +/- constant) pattern as it is the most common hidden logic in SSC/Railway exams.
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