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Select the set in which the numbers are related in the same way as are the numbers of the following sets. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 тАУ Operations on 13 such as adding / subtracting /multiplying, etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) (133,5,23) (107,1,18)
(76,20,16)
(10,22,2)
(75,9,4)
(18,24,1)
(76,20,16)
Look for the relationship where the difference between the first two numbers is divided by a constant to get the third number: (First - Second) / 6 = Third.
Look for the relationship where the difference between the first two numbers is divided by a constant to get the third number: (First - Second) / 6 = Third.
Analyze the first set (133, 5, 23)
Calculate the difference between the first and second number: 133 - 5 = 128. Then divide by the third number: 128 / 23 does not yield a clean integer, so try 133 - (23 * 5) = 133 - 115 = 18. Alternatively: (133 - 5) / 6 is not it. Let us try: 133 - (5 * 23) = 18. Wait, looking at the pattern (133, 5, 23): 133 - 5 = 128; 128 / 23 is not integer. Let us try: (133 + 5) / 6 = 138 / 6 = 23.
Verify the logic with the second set (107, 1, 18)
Apply the rule (Number1 + Number2) / 6 = Number3. For (107, 1, 18): (107 + 1) = 108. 108 / 6 = 18. The pattern (Num1 + Num2) / 6 = Num3 holds true for both given sets.
Apply logic to the options
Test Option A (76, 20, 16): (76 + 20) = 96. 96 / 6 = 16. This matches the established pattern perfectly.
B: (10 + 22) / 6 = 32 / 6 = 5.33 (not 2); C: (75 + 9) / 6 = 84 / 6 = 14 (not 4); D: (18 + 24) / 6 = 42 / 6 = 7 (not 1).
A is correct because the logic (First + Second) / 6 = Third is satisfied only by the set (76, 20, 16).
When dealing with sets of three numbers, always test the relationship (A+B)/C, (A-B)/C, or (A*B)/C first as they are the most common patterns in competitive exams.
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