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ElectricalMachine
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Size (product of ЁЭР╖┬▓ ЁЭР┐) of the machine depends on which of the following parameters?

A

Output of the machine

B

Output Co-efficient of the machine

C

Synchronous Speed of the machine

D

All of these

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalMachine
Option D

All of these

Quick Summary:

The physical size of an electrical machine is represented by its main dimensions, the stator bore diameter (DDD) and the core length (LLL). The product D2LD^2LD2L determines the volume of the active material required and is directly proportional to the output rating and inversely proportional to the speed and the output coefficient of the machine.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The physical size of an electrical machine is represented by its main dimensions, the stator bore diameter (DDD) and the core length (LLL). The product D2LD^2LD2L determines the volume of the active material required and is directly proportional to the output rating and inversely proportional to the speed and the output coefficient of the machine.

ЁЯФв Key Formulas

D2L=QC0nsD^2 L = \frac{Q}{C_0 n_s}D2L=C0тАЛnsтАЛQтАЛ тАФ fundamental output equation relating volume to rating, coefficient, and speed.

C0=11Bavac├Ч10тИТ3C_0 = 11 B_{av} ac \times 10^{-3}C0тАЛ=11BavтАЛac├Ч10тИТ3 тАФ defines the output coefficient in terms of specific magnetic loading (BavB_{av}BavтАЛ) and electric loading (acacac).

тЪЩя╕П Working Principle

The design of a rotating machine is governed by the output equation Q=C0D2LnsQ = C_0 D^2 L n_sQ=C0тАЛD2LnsтАЛ, where QQQ is the power rating, C0C_0C0тАЛ is the output coefficient (which depends on magnetic and electric loadings), and nsn_snsтАЛ is the synchronous speed. Thus, D2L=QC0nsD^2 L = \frac{Q}{C_0 n_s}D2L=C0тАЛnsтАЛQтАЛ. This relationship implies that for a fixed output, increasing the speed or the efficiency of material utilization (output coefficient) allows for a smaller machine size.

ЁЯУМ Key Points
  • тЦ╕

    The product D2LD^2LD2L is known as the output constant or machine size constant.

  • тЦ╕

    Higher output coefficient C0C_0C0тАЛ implies better utilization of active material, leading to a smaller D2LD^2LD2L for a given rating.

  • тЦ╕

    For higher synchronous speeds, the required D2LD^2LD2L decreases for a constant power rating.

  • тЦ╕

    Magnetic loading (BavB_{av}BavтАЛ) and Electric loading (acacac) are constrained by the saturation of iron and thermal limits of insulation respectively.

тЬЕ Advantages
  • тЦ╕

    Allows for standardized sizing of electrical machines.

  • тЦ╕

    Provides a clear design pathway for selecting motor frame sizes.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Requires iterative design processes to optimize DDD vs LLL ratios.

  • тЦ╕

    Does not account for non-active material requirements like casing and cooling fins.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Preliminary sizing of Induction Motors.

  • тЦ╕

    Performance optimization of Synchronous Generators.

ЁЯУД Additional Information
  • тЦ╕

    The Output Coefficient C0C_0C0тАЛ is constant for a specific type of machine (e.g., induction motor) and cooling method.

  • тЦ╕

    Option B (Output Co-efficient) is a measure of how efficiently the flux density and current density are utilized in the machine space.

ЁЯУК Diagram / Illustration
Output Equation (Main Dimensions)D┬▓ L = Output / (CтВА ├Ч nтВЫ)Output (Q)Output Coefficient (CтВА) ├Ч Synchronous Speed (nтВЫ)
тЬЕ

D is correct тАФ The machine size D2LD^2LD2L is directly derived from the output equation, making it a function of the machine's power output, its design efficiency (output coefficient), and its operating speed.

Core Concepts Used
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Output Equation Specific Magnetic Loading Specific Electric Loading
ЁЯТб EXAM TIP

Always remember that for a given D2LD^2LD2L, increasing nsn_snsтАЛ (synchronous speed) allows the machine to provide more power output (or handle a larger load).

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