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Solve for x: 3x + 5 = 17 - x
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3
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3
Use option substitution: Quickly plug in options into both sides. If x = 3, LHS = 3(3)+5 = 14 and RHS = 17-3 = 14. Since 14 = 14, B is the answer.
An algebraic equation 3x + 5 = 17 - x is provided.
ax+b=cx+dтЯ╣x=aтИТcdтИТbтАЛ
Use option substitution: Quickly plug in options into both sides. If x = 3, LHS = 3(3)+5 = 14 and RHS = 17-3 = 14. Since 14 = 14, B is the answer.
Students often forget to change the sign of the variable when moving it across the equality sign, such as writing -x as -x instead of +x on the left side.
Group like terms
Collect the variable terms on the left side by adding x to both sides and moving constant terms to the right side by subtracting 5.
3x+x=17тИТ5
Simplify the equation
Combine the coefficients of x and perform the arithmetic on the constants.
4x=12
Solve for x
Divide both sides by 4 to isolate x.
x=412тАЛ=3
B is correct because solving the equation 3x+5=17тИТx yields the value x=3.
This fundamental algebraic skill is essential for solving more complex quadratic equations and ratio-based problems in Quantitative Aptitude.
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