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Diagram

10V

40V

30V

20V

Correct Answer

⚙️ TE • Technical Concept & PrincipleTechnical AbilityElectrical Circuit Theory

Option B

40V

Quick Summary:

The output voltage $V_{o}$ is determined by the input voltage $V_{i}$ and the potential of the series-connected battery when the diode is forward-biased. The circuit acts as a positive clamper or a series-biased clipper depending on the reference node; here, the output voltage is $V_{o} = V_{i} + 10\text{V}$ when the diode conducts.

⚙️TETechnical SolutionConcept & Principle

💡 Explanation

🔢 Key Formulas

$V_{o, \text{peak}} = V_{i, \text{peak}} + V_{\text{battery}}$

$V_{i} = 30 \sin(\omega t)$

⚙️ Working Principle

When the input voltage $V_{i}$ exceeds the threshold of the diode (assuming an ideal diode), the diode becomes forward-biased. Under this condition, the loop equation gives $V_{o} = V_{i} + 10\text{V}$ . Since $V_{i}$ is a sinusoidal wave with a peak of $30\text{V}$ , the maximum positive peak of the output will be $30\text{V} + 10\text{V} = 40\text{V}$ .

📌 Key Points

▸
The diode allows current to flow when the cathode is at a lower potential than the anode.
▸
The battery is in series with the input, effectively shifting the peak value of the input signal.
▸
The peak value of the input is $30\text{V}$ and the battery contributes an additional $10\text{V}$ to the output signal during conduction.

✅ Advantages

▸
Provides a simple method for DC level shifting
▸
Efficient signal modification

❌ Disadvantages / Limitations

▸
Ideal diode assumption ignores $0.7\text{V}$ forward voltage drop
▸
Circuit is limited to positive peak shifting

🛠️ Applications / Uses

▸
Signal conditioning
▸
DC level restoration in communication systems

📄 Additional Information

▸
In practical conditions, if the diode is silicon, the output would be $V_{o} = V_{i} + 10\text{V} - 0.7\text{V} = 39.3\text{V}$ .
▸
The provided answer key assumes an ideal diode and sums the input peak with the battery source voltage.

📊 Diagram / Illustration

✅

B is correct — The peak output voltage is obtained by summing the peak input voltage of $30\text{V}$ with the $10\text{V}$ source, resulting in $40\text{V}$ .

Core Concepts Used

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Diode Circuit Analysis Voltage Clamping Series Biasing

💡 EXAM TIP

When analyzing biased diode circuits, always verify the polarity of the battery relative to the diode to determine if it aids or opposes the input voltage.

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