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CivilStructural Mechanics-II
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The equation for normal stress on inclined plane is

A

σn=σ1−σ22+σ1+σ22cos⁡2θ+τsin⁡2θσ_{n} = σ_{1} - σ_{2} 2 + σ_{1} + σ_{2} 2 \cos 2 \theta + τ \sin 2 \thetaσn​=σ1​−σ2​2+σ1​+σ2​2cos2θ+τsin2θ

B

σn=σ1+σ22−σ1−σ22cos⁡2θ−τsin⁡2θσ_{n} = σ_{1} + σ_{2} 2 - σ_{1} - σ_{2} 2 \cos 2 \theta - τ \sin 2 \thetaσn​=σ1​+σ2​2−σ1​−σ2​2cos2θ−τsin2θ

C

σn=σ1+σ22+σ1−σ22cos⁡2θ−τsin⁡2θσ_{n} = σ_{1} + σ_{2} 2 + σ_{1} - σ_{2} 2 \cos 2 \theta - τ \sin 2 \thetaσn​=σ1​+σ2​2+σ1​−σ2​2cos2θ−τsin2θ

D

σn=σ1+σ22+σ1−σ22cos⁡2θ+τsin⁡2θσ_{n} = σ_{1} + σ_{2} 2 + σ_{1} - σ_{2} 2 \cos 2 \theta + τ \sin 2 \thetaσn​=σ1​+σ2​2+σ1​−σ2​2cos2θ+τsin2θ

Correct Answer

⚙️ TE • Technical Verified SolutionCivilStructural Mechanics-II
Option D

σn=σ1+σ22+σ1−σ22cos⁡2θ+τsin⁡2θσ_{n} = σ_{1} + σ_{2} 2 + σ_{1} - σ_{2} 2 \cos 2 \theta + τ \sin 2 \thetaσn​=σ1​+σ2​2+σ1​−σ2​2cos2θ+τsin2θ

Quick Summary:

Practice and solve "The equation for normal stress on inclined plane is..." for Civil - Structural Mechanics-II. The correct answer is Option D: σn=σ1+σ22+σ1-σ22cos2θ+τsin2θ. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.

Option **(d) **

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