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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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CivilStructural Mechanics-II
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The fixed beam having a length l and point load W kN at its mid point of the span, the equation of fixed end moment for this beam is

A

wl212\frac{wl^2}{12}12wl2​

B

Wl4\frac{Wl}{4}4Wl​

C

Wl8\frac{Wl}{8}8Wl​

D

wl28\frac{wl^2}{8}8wl2​

Correct Answer

⚙️ TE • Technical Concept & PrincipleCivilStructural Mechanics-II
Option C

Wl8\frac{Wl}{8}8Wl​

Quick Summary:

For a fixed-fixed beam of length lll subjected to a central point load WWW, the fixed end moments (MAM_AMA​ and MBM_BMB​) arise due to the rotational restraint at the supports. Using the theorem of consistent deformation or the moment-area method, the fixed end moment is calculated as Wl8\frac{Wl}{8}8Wl​.

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

For a fixed-fixed beam of length lll subjected to a central point load WWW, the fixed end moments (MAM_AMA​ and MBM_BMB​) arise due to the rotational restraint at the supports. Using the theorem of consistent deformation or the moment-area method, the fixed end moment is calculated as Wl8\frac{Wl}{8}8Wl​.

🔢 Key Formulas

MF=Wl8M_F = \frac{Wl}{8}MF​=8Wl​ — Fixed end moment for central point load

MF=wl212M_F = \frac{wl^2}{12}MF​=12wl2​ — Fixed end moment for Uniformly Distributed Load (UDL)

⚙️ Working Principle

In a statically indeterminate beam with fixed ends, the supports prevent rotation. Applying a point load WWW at the center causes a downward deflection. The fixed ends generate restraining moments MFM_FMF​ that oppose this rotation, ensuring the slope remains zero at the supports. By symmetry, the moments at both ends are equal, and equilibrium requires the internal resisting moment to counteract the externally induced bending moment.

📌 Key Points
  • ▸

    Fixed beams are statically indeterminate to the second degree.

  • ▸

    The fixed end moment for a central point load is independent of the flexural rigidity (EI) as long as the beam is uniform.

  • ▸

    Bending moment at the center of the beam is Wl8\frac{Wl}{8}8Wl​.

✅ Advantages
  • ▸

    Higher stiffness compared to simply supported beams.

  • ▸

    Significant reduction in maximum mid-span deflection.

❌ Disadvantages / Limitations
  • ▸

    Sensitive to support settlements, which induce additional stresses.

  • ▸

    Temperature changes induce internal thermal stresses.

🛠️ Applications / Uses
  • ▸

    Rigidly connected frames in high-rise buildings.

  • ▸

    Continuous beam bridge decks.

📄 Additional Information
  • ▸

    Option A (wl212\frac{wl^2}{12}12wl2​) is the fixed end moment for a beam subjected to a UDL.

  • ▸

    Option B (Wl4\frac{Wl}{4}4Wl​) is the maximum bending moment for a simply supported beam with a central point load.

  • ▸

    Option D (wl28\frac{wl^2}{8}8wl2​) is the maximum bending moment for a simply supported beam with a UDL.

📊 Diagram / Illustration
Fixed End MomentWl8
✅

C is correct — The fixed end moment for a beam of length lll with a central point load WWW is Wl8\frac{Wl}{8}8Wl​.

Core Concepts Used
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Statically Indeterminate Structures Fixed End Moments Structural Equilibrium
💡 EXAM TIP

Always distinguish between 'W' (point load) and 'w' (load per unit length) as examiners often use them to differentiate between point load and UDL formulas.

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