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ElectricalElectronics
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The following is the first London equation

A

dJsdx=nsq2Emd J_{s} d x = n_{s} q^{2} E mdJsā€‹dx=nsā€‹q2Em

B

dJs=nsq2EmdEd J_{s} = n_{s} q^{2} E m d EdJsā€‹=nsā€‹q2EmdE

C

dJsdt=nsEmd J_{s} d t = n_{s} E mdJsā€‹dt=nsā€‹Em

D

dJsdt=nsq2Emd J_{s} d t = n_{s} q^{2} E mdJsā€‹dt=nsā€‹q2Em

Correct Answer

āš™ļø TE ā€¢ Technical Verified SolutionElectricalElectronics
Option D

dJsdt=nsq2Emd J_{s} d t = n_{s} q^{2} E mdJsā€‹dt=nsā€‹q2Em

Quick Summary:

Practice and solve "The following is the first London equation..." for Electrical - Electronics. The correct answer is Option D: dJsdt = ns q2 Em. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.

Option **(d) **

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