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ElectricalPower System
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The impedance per phase of 3-phase transmission line on a base of 100 MVA, 100 kV is 2 pu. The value of this impedance on a base of 400 MVA and 400 kV would be

A

pu

B

pu

C

pu

D

25 pu

Correct Answer

тЪЩя╕П TE тАв Technical Direct FormulaElectricalPower System
Option A

pu

Quick Summary:

Given: Initial Base: MVAoldMVA_{old}MVAoldтАЛ = 100 MVA, kVoldkV_{old}kVoldтАЛ = 100 kV, Impedance Z_pu_old = 2 pu. New Base: MVAnewMVA_{new}MVAnewтАЛ = 400 MVA, kVnewkV_{new}kVnewтАЛ = 400 kV.

ЁЯУРMAMath SolutionDirect Formula
ЁЯУЛ Given

Initial Base: MVAoldMVA_{old}MVAoldтАЛ = 100 MVA, kVoldkV_{old}kVoldтАЛ = 100 kV, Impedance Z_pu_old = 2 pu. New Base: MVAnewMVA_{new}MVAnewтАЛ = 400 MVA, kVnewkV_{new}kVnewтАЛ = 400 kV.

ЁЯФв Formula Used

Zpu,new=Zpu,old├Ч(MVAnewMVAold)├Ч(kVoldkVnew)2Z_{pu,new} = Z_{pu,old} \times \left( \frac{MVA_{new}}{MVA_{old}} \right) \times \left( \frac{kV_{old}}{kV_{new}} \right)^2Zpu,newтАЛ=Zpu,oldтАЛ├Ч(MVAoldтАЛMVAnewтАЛтАЛ)├Ч(kVnewтАЛkVoldтАЛтАЛ)2

ЁЯФв Step-by-Step Solution
1

Identify the per-unit change formula

To change the base of per-unit impedance, we use the conversion relationship based on the definitions of per-unit values: Zpu=ZactualZbaseZ_{pu} = \frac{Z_{actual}}{Z_{base}}ZpuтАЛ=ZbaseтАЛZactualтАЛтАЛ where Zbase=(kV)2MVAZ_{base} = \frac{(kV)^2}{MVA}ZbaseтАЛ=MVA(kV)2тАЛ.

Zpu,new=Zpu,old├ЧMVAnewMVAold├Ч(kVoldkVnew)2Z_{pu,new} = Z_{pu,old} \times \frac{MVA_{new}}{MVA_{old}} \times \left( \frac{kV_{old}}{kV_{new}} \right)^2Zpu,newтАЛ=Zpu,oldтАЛ├ЧMVAoldтАЛMVAnewтАЛтАЛ├Ч(kVnewтАЛkVoldтАЛтАЛ)2

2

Substitute the given values

Substitute Zpu,old=2Z_{pu,old} = 2Zpu,oldтАЛ=2, MVAnew=400MVA_{new} = 400MVAnewтАЛ=400, MVAold=100MVA_{old} = 100MVAoldтАЛ=100, kVold=100kV_{old} = 100kVoldтАЛ=100, and kVnew=400kV_{new} = 400kVnewтАЛ=400 into the formula.

Zpu,new=2├Ч(400100)├Ч(100400)2Z_{pu,new} = 2 \times \left( \frac{400}{100} \right) \times \left( \frac{100}{400} \right)^2Zpu,newтАЛ=2├Ч(100400тАЛ)├Ч(400100тАЛ)2

3

Calculate the result

Simplify the expression: 2├Ч4├Ч(1/4)2=8├Ч(1/16)=0.52 \times 4 \times (1/4)^2 = 8 \times (1/16) = 0.52├Ч4├Ч(1/4)2=8├Ч(1/16)=0.5.

Zpu,new=8├Ч116=0.5Z_{pu,new} = 8 \times \frac{1}{16} = 0.5Zpu,newтАЛ=8├Ч161тАЛ=0.5

тЬЕ

A is correct because applying the change of base formula yields a new impedance of 0.5 pu.

Core Concepts Used
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Per-unit system Change of Base Transmission Line Modeling
ЁЯТб EXAM TIP

Always remember the base impedance ZbaseZ_{base}ZbaseтАЛ is directly proportional to (kV)2(kV)^2(kV)2 and inversely proportional to MVAMVAMVA, which is why the voltage ratio is squared while the power ratio is linear.

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