Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
The interior angles of a triangle are (3x+10)°, (2x−5)° and (x+25)°. Find the value of x.
20
25
30
35
25
Sum the coefficients of x (3+2+1 = 6) and the constant terms (10-5+25 = 30). Then solve 6x + 30 = 180, which simplifies to 6x = 150, giving x = 25.
The three interior angles of a triangle are given as (3x + 10)°, (2x - 5)°, and (x + 25)°.
∠A+∠B+∠C=180°
Sum the coefficients of x (3+2+1 = 6) and the constant terms (10-5+25 = 30). Then solve 6x + 30 = 180, which simplifies to 6x = 150, giving x = 25.
Students often make sign errors when simplifying the constant terms (10 - 5 + 25), frequently miscalculating 30 as 20 or 40.
Set up the equation
According to the Angle Sum Property of a triangle, the sum of all interior angles is always 180°.
(3x+10)+(2x−5)+(x+25)=180
Group like terms
Combine the variable terms (3x+2x+x) and the constant terms (10−5+25).
6x+30=180
Solve for x
Subtract 30 from both sides and then divide by 6 to isolate x.
6x=150⟹x=6150=25
B is correct because the substitution of x=25 satisfies the triangle interior angle sum property 180°.
This concept is a precursor to coordinate geometry problems where you determine if three points form a valid triangle by checking their internal angles.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants