Join 60,000+ competitive exam aspirants
The mean of 5 observations is 15. If one observation 25 is removed, what is the new mean?
12.5
10
15
13
12.5
New mean = old mean тИТnew┬аcountremoved┬аvalueтИТold┬аmeanтАЛ = 15 тИТ425тИТ15тАЛ = 15 - 2.5 = 12.5.
Number of observations n = 5, mean = 15, removed observation = 25
New┬аMean=New┬аCountInitial┬аSumтИТRemoved┬аValueтАЛ
New mean = old mean тИТnew┬аcountremoved┬аvalueтИТold┬аmeanтАЛ = 15 тИТ425тИТ15тАЛ = 15 - 2.5 = 12.5.
Dividing the difference by the old count (5) instead of the new count (4).
Find Initial Sum
Multiply the number of observations (n=5) by the given mean (15).
Sum=5├Ч15=75
Calculate New Sum
Subtract the removed observation (25) from the initial sum (75).
New┬аSum=75тИТ25=50
Find New Count
Subtract 1 from the total number of observations since one observation is removed.
New┬аCount=5тИТ1=4
Compute New Mean
Divide the new sum by the new count of observations.
New┬аMean=450тАЛ=12.5
A is correct because the new mean of the remaining 4 observations is 12.5.
The deviation-distribution shortcut saves critical time in RRB and SSC CBT exams for mean, weight replacement, and average score modification problems.