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The quadratic equation whose roots are 2/3 and 3/2 is:
6x² - 13x + 6 = 0
6x² + 13x + 6 = 0
4x² - 13x + 9 = 0
9x² - 13x + 4 = 0
6x² - 13x + 6 = 0
Find the sum of roots (613) and product of roots (1), then multiply the entire equation by the denominator 6 to clear fractions quickly.
Roots of the quadratic equation are α=32 and β=23
x2−(α+β)x+αβ=0
Find the sum of roots (613) and product of roots (1), then multiply the entire equation by the denominator 6 to clear fractions quickly.
Students often make calculation errors when adding fractions with different denominators or forget to multiply by the LCM to clear fractions.
Identify Sum and Product of Roots
Given roots are α=32 and β=23. Calculate their sum and product.
α+β=32+23=64+9=613
Calculate Product of Roots
Multiply the two roots together to find the constant term coefficient value.
αβ=(32)×(/23)=1
Substitute into Quadratic Equation Formula
Use the standard quadratic equation formula given by sum and product of roots.
x2−(613)x+1=0
Simplify and Clear Denominators
Multiply the entire equation by 6 to eliminate the fraction and obtain integer coefficients.
6x2−13x+6=0
A is correct because the quadratic equation formed using the roots 32 and 23 simplifies to 6x2−13x+6=0.
Understanding the relationship between roots and coefficients helps quickly solve higher-degree polynomial equations and symmetric function problems in competitive exams.