Define the Variables

Let the Principal amount deposited be $P$. Given $P = x\% \text{ of } 60000 = \frac{x}{100} \times 60000 = 600x$. The accumulated amount $A$ is $15600$ and Rate $R = 10\%$ per annum for $T = 2$ years.

$P = 600x, \quad A = 15600, \quad R = 10\%, \quad T = 2$

Apply Amount Formula

The formula for the total accumulated amount is $A = P + \text{SI}$, where $\text{SI} = \frac{P \times R \times T}{100}$. Substituting the values, we get $15600 = P(1 + \frac{10 \times 2}{100})$.

$15600 = P \left(1 + \frac{20}{100}\right) = 1.2P$

Calculate Principal P

Solving for $P$, we have $P = \frac{15600}{1.2} = 13000$.

$P = 13000$

Find x

Since $P = 600x$, we equate $600x = 13000$. Thus, $x = \frac{13000}{600} = \frac{130}{6} \approx 21.67$. Wait, let's recheck the calculation. The option provided is 20, which implies $12000$ deposited. $1.2 \times 12000 = 14400$. Re-evaluating: if $x=20$, $P=12000$, $A=14400$. If $A=15600$ and $R=10, T=2$, then $P=13000$, $x=13000/600=21.66$. Given the answer key, there might be a typo in the question's target value.

$x = \frac{13000}{600} = 21.67$