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The sum of length, breadth, and height of a cuboid is 12 cm and its diagonal is 8 cm. Find its total surface area.
80 sq cm
64 sq cm
144 sq cm
100 sq cm
80 sq cm
Use the algebraic identity (l+b+h)2тИТ(d2)=Total┬аSurface┬аArea, where d2=l2+b2+h2. Simply calculate 122тИТ82=144тИТ64=80.
Sum of dimensions (length, breadth, and height) = 12 cm, Diagonal of cuboid = 8 cm.
(l+b+h)2=l2+b2+h2+2(lb+bh+hl)
Use the algebraic identity (l+b+h)2тИТ(d2)=Total┬аSurface┬аArea, where d2=l2+b2+h2. Simply calculate 122тИТ82=144тИТ64=80.
Students often confuse the formula for the diagonal (d=l2+b2+h2тАЛ) with the sum of dimensions (l+b+h) and try to solve for individual dimensions, which is not required.
Define given variables
Let the dimensions of the cuboid be l, b, and h. We are given the sum l+b+h=12 and the diagonal d=l2+b2+h2тАЛ=8.
l+b+h=12,l2+b2+h2=82=64
Apply algebraic identity
The total surface area (TSA) of a cuboid is given by 2(lb+bh+hl). We use the expansion of (l+b+h)2.
(l+b+h)2=l2+b2+h2+2(lb+bh+hl)
Substitute and calculate
Substitute the known values into the equation: 122=64+TSA. Solving for TSA gives 144тИТ64=80.
TSA=144тИТ64=80
A is correct because the total surface area calculated using the identity (l+b+h)2тИТd2 results in 80 sq cm.
This identity-based approach is frequently tested in 'Algebra' sections of competitive exams, specifically under problems involving symmetric polynomials.