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The sum of three consecutive integers is 126. What is the largest integer?
41
42
43
44
43
To find three consecutive integers that sum to 126, represent them as x-1, x, and x+1. The sum 3x = 126 results in x = 42, making the integers 41, 42, and 43, where 43 is the largest.
To find three consecutive integers that sum to 126, represent them as x-1, x, and x+1. The sum 3x = 126 results in x = 42, making the integers 41, 42, and 43, where 43 is the largest.
This mathematical property of consecutive integers is a fundamental algebraic concept frequently tested in RRB, SSC, and UPSC CSAT aptitude sections.
Sum of n consecutive integers is always divisible by n if n is odd.
For three consecutive integers, the average is always the middle integer.
The sum of any three consecutive integers is equal to three times the middle integer.
Average calculation: 126 divided by 3 equals 42, which is the middle term.
Verification: 41 plus 42 plus 43 equals 126.
Option B (42) represents the middle integer (the average), not the largest.
Option A (41) represents the smallest integer in the sequence.
C is correct тАФ The sequence consists of 41, 42, and 43, making 43 the largest integer.
In competitive exams, always check if the question asks for the smallest, largest, or middle integer to avoid common errors when working with number sequences.
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