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The value of 23−42+(12/3)2−0+5×2 is:
18
20
22
24
18
Calculate individual terms independently while maintaining the signs: 23=8, 42=16, (12/3)2=42=16, and 5×2=10. Then solve 8−16+16−0+10.
The expression given is 2³ - 4² + (12 / 3)2 - 0 + 5 * 2.
BODMAS: Brackets, Orders, Division, Multiplication, Addition, Subtraction
Calculate individual terms independently while maintaining the signs: 23=8, 42=16, (12/3)2=42=16, and 5×2=10. Then solve 8−16+16−0+10.
Many students mistake the order of operations by performing subtraction before multiplication or failing to evaluate the exponent (12/3)2 correctly.
Evaluate Exponents and Brackets
Simplify the powers and the term inside the parenthesis: 23=8, 42=16, and (12/3)2=42=16.
8−16+16−0+5×2
Perform Multiplication
Next, apply the multiplication step from BODMAS: 5×2=10.
8−16+16−0+10
Perform Addition and Subtraction
Simplify the final expression from left to right: 8−16=−8, −8+16=8, 8−0=8, and 8+10=18.
18
A is correct because the step-by-step simplification of the expression 8−16+16−0+10 results in 18.
Always identify the structure of the expression first; in competitive exams, look for additive inverse pairs like −16 and +16 to cancel them out instantly.
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