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Examoogle • User • info@examoogle.com • EE-2024-8821
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The voltages at the two ends of a line are 132 kV and its reactance is 40 Ω. The capacity of the line is
435.6 MW
217.5 MW
251.5 MW
500 MW
435.6 MW
Given: Voltage V = 132 kV, Reactance X = 40 Ω.
Voltage V = 132 kV, Reactance X = 40 Ω.
P=XV2
Identify given parameters
The line voltage V is given as 132 kV and the line reactance X is 40 Ω.
V=132×103 V,X=40 Ω
Apply Steady State Stability Limit formula
The capacity of the transmission line (maximum power transfer) is determined by the formula P=XV2 where δ=90° for maximum power.
P=40(132×103)2
Calculate the power
Calculating the value: P=4017424×106=435.6×106 W. Converting to MW gives 435.6 MW.
P=435.6 MW
A is correct because the maximum power capacity of the line calculated using the steady-state stability formula is 435.6 MW.
This formula is a fundamental concept in Power System Stability analysis; it assumes a lossless line where the maximum power transfer occurs at a load angle of 90°.