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This question is based on the following words. FON MEN OPS PVT In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding it in the English alphabetical order. In how many letter-clusters thus formed, will no vowel appear?
Three
One
Four
Two Question ID : 441009819457 Option 1 ID : 4410093231952 Option 2 ID : 4410093231954 Option 3 ID : 4410093231951 Option 4 ID : 4410093231953 Status : Answered Chosen Option : B
One
Focus only on whether the resulting letter becomes a vowel (A, E, I, O, U). Since only vowels increase and consonants decrease, identify if any original consonant becomes a vowel (e.g., B, F, J, P, V) or any vowel stays a vowel.
Focus only on whether the resulting letter becomes a vowel (A, E, I, O, U). Since only vowels increase and consonants decrease, identify if any original consonant becomes a vowel (e.g., B, F, J, P, V) or any vowel stays a vowel.
Mapping Rules
Rule 1: Vowel (A, E, I, O, U) becomes next letter (+1). Rule 2: Consonant becomes previous letter (-1).
Processing Word Clusters
1. FON: F(C:-1)=E, O(V:+1)=P, N(C:-1)=M. Result: EPM (Contains Vowel 'E'). 2. MEN: M(C:-1)=L, E(V:+1)=F, N(C:-1)=M. Result: LFM (No Vowel). 3. OPS: O(V:+1)=P, P(C:-1)=O, S(C:-1)=R. Result: POR (Contains Vowel 'O'). 4. PVT: P(C:-1)=O, V(C:-1)=U, T(C:-1)=S. Result: OUS (Contains Vowels 'O' and 'U').
Final Count
Out of the four transformed clusters (EPM, LFM, POR, OUS), only 'LFM' contains no vowels. Thus, the count is 1.
A: The count is 1, not 3. C: The count is 1, not 4. D: The count is 1, not 2.
B is correct because after applying the transformation rules, only the letter-cluster 'MEN' transforms into 'LFM', which contains no vowels, while the other three retain vowels.
In transformation questions, always list the vowels (A, E, I, O, U) first. Remember that consonants include everything else, and check if the transformed letter shifts into or out of the vowel set.
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