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This question is based on the following words. BAS HIS JEM BOL In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding it in the English alphabetical order. In how many letter-clusters thus formed, will no vowel appear?
Three
One
Four
Two Question ID : 4410091599077 Option 1 ID : 4410096316101 Option 2 ID : 4410096316099 Option 3 ID : 4410096316102 Option 4 ID : 4410096316100 Status : Answered Chosen Option : B
One
Instead of converting the entire word, check for vowels first; if the original word has a vowel, only the transformation determines if it remains a vowel.
Instead of converting the entire word, check for vowels first; if the original word has a vowel, only the transformation determines if it remains a vowel.
Mapping Rules
Rule: Vowel (A, E, I, O, U) тЖТ Next letter (+1); Consonant тЖТ Previous letter (-1). Words: BAS, HIS, JEM, BOL.
Transformation Analysis
BAS: B(C-1)=A, A(V+1)=B, S(C-1)=R тЖТ ABR (Contains 'A', vowel present). HIS: H(C-1)=G, I(V+1)=J, S(C-1)=R тЖТ GJR (No vowel). JEM: J(C-1)=I, E(V+1)=F, M(C-1)=L тЖТ IFL (Contains 'I', vowel present). BOL: B(C-1)=A, O(V+1)=P, L(C-1)=K тЖТ APK (Contains 'A', vowel present).
Counting Clusters
Only GJR (derived from HIS) has no vowel. The clusters are ABR, GJR, IFL, APK. Only one cluster satisfies the condition.
A: Three is incorrect as only one cluster satisfies the condition. C: Four is incorrect as three clusters contain vowels. D: Two is incorrect as only GJR is free of vowels.
B is correct because only the cluster GJR, formed from HIS, contains no vowels after the specified alphabetical transformations.
In transformation questions, always list vowels clearly at the start to avoid confusing them with consonants during rapid calculation.
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